Question 246699
solve the inequality x squared - x >12

So we have x^2 - x > 12

Then x^2 - x - 12 > 0

(x-4)*( x+3) > 0

We know that x-4 and x+3 must have the same sign so: 

When x-4 > 0, 
x+3 is also > 0. 

When x-4 < 0, 
x+3 is also < 0. 

The solution set is the union of all values of x that make these two pairs of inequalities true.