Question 246678
log[3](1-x)+log[3](2-x)=log[3](7)
log[3](1-x)(2-x)=log[3](7)
(1-x)(2-x)=7
2-x-2x+x^2=7
2-3x+x^2=7
x^2-3x+2=7
x^2-3x-5=0
Applying the quadratic equation will yield:
x = {4.193, -1.193}
Checking for extraneous solutions:
We can throw out the 4.193 solution because it will give us a negative log. So:
x = {-1.193}
.
Details of quadratic to follow:
*[invoke quadratic "x", 1, -3, -5 ]