Question 246586
f(x)=x^2+5x+2
x^2+5x+2=0
x^2+5x   =-2
x^2+5x+25/4=25/4 -2 completing the square
(x+ 5/2)^2=17/4
x+ 5/2=+-sqrt(17)/2
x=-5/2+-sqrt(17)/2
x=-(5+sqrt(17))/2, x=-(5-sqrt(17))/2 The x intercepts.
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-b/2a=axis of symmetry=-5/2
x^2+5x+2=-17/4 (the minimum) when x=-5/2
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Ed
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{{{graph(500,500,-10,10,-10,10,x^2+5x+2)}}}