Question 246385
Hint: Let {{{z=sec(x)}}}. So {{{z^2=(sec(x))^2}}} which means that the equation {{{(sec(x))^2-sec(x)=2}}} becomes {{{z^2-z=2}}}. Use the quadratic formula to solve for 'z'. Once you have the solutions in terms of z, use them to find the solutions in terms of x.