Question 246361
y = x^2 + 4x
y = x(x+4)
.
x=0
x=-4
.
Checking our work...
.
y = x^2 + 4x
x = 0
y = 0^2 + 4(0) = 0
OK
.
y = x^2 + 4x
x = -4
y = (-4)^2 + (4)(-4)
y = 16 + (-16) = 0
OK