Question 246318
if you assume a B average is 80, and if the weighting for all the tests is equal and you are only talking about 2 tests, then:


(x + 88)/2 = 80


multiply both sides of this equation by 2 to get:


x + 88 = 160


subtract 88 from both sides of this equation to get:


x = 160-88 = 72


lowest score you can get is 72 to keep an 80 average.


72 + 88 = 160/2 = 80