Question 246311
26 letters in the alphabet.
10 numbers (0 through 9)


you have 3 letters followed by 2 digits.


that would be:


26*26*26*10*10 = 1757600 possible combinations


here's how it works.


assume only 3 letters (abc) and only 2 number (01) are possible in each position.


assume only 3 positions (2 letters and 1 number)


that would be 3 * 3 * 2 = 18 possible combinations


they would be:


aa1
aa2
ab1
ab2
ac1
ac2
ba1
ba2
bb1
bb2
bc1
bc2
ca1
ca2
cb1
cb2
cc1
cc2