Question 246295
2(5X)+2(3X)=64
10X+6X=64
16X=64
X=64/16
X=4 
5*4=20 ANS. FOR ONE SIDE.
3*4=12 ANS. FOR THE OTHER SIDE.
PROOF:
5:3=20:12 REDUCE THE FRACTION.
5:3=5:3
2*20+2*12=64
40+24=64
64=64
SOLVE FOR THE HYPOTENUSE OF THIS RIGHT TRIANGLE WITH SIDES=12 & 20.
12^2+20^2=C^2
144+400=C^2
544=C^2
C=SQRT544
C=23.324 ANS. FOR THE DIAGONAL.