Question 246244
You are correct down to the last step, but your last step is wrong!!  There is NO DISTRIBUTIVE property in LOGARITHMS!  In other words, log(x+y) does NOT equal log(x) + log(y).


You are correct to here:
logV-logVmax= nlogs-log(Km^n+s^n) 



Now, solve for nlogs by addding +log(Km^n+s^n} to each side:
log V + log(Km^n+s^n) - logVmax= nlogs


Then apparently, you have to solve for Km^n+s^n in the original equation, Km^n+s^n = Vmax*s^n/V(s).


I'm not sure how to finish this, but here is a thought for you.


and substitute this into the equation above:
log V + log(Km^n+s^n) - logVmax= nlogs
log V + log(Vmax*s^n/V(s)) - logVmax= nlogs


Good luck.  If I get time, I'll come back and give this some more thought.  Meantime, maybe you can re-post this or work on it yourself.


Dr. Robert J. Rapalje