Question 246214
<pre><font size = 4 color = "indigo"><b>
To draw the graph of

{{{y=A*abs(Bx+C) + D}}}

1.  The graph is always a V-shaped graph, either
an upright V or an upside-down V. It will be right-side
up if A, the coefficient, written or understood, of the 
absolute value is positive and upside-down if it is 
negative.

2. Find the x-coordinate of the vertex (the "sharp point" 
of the V) by setting the expression within the absolute 
value bars, {{{Bx+C = 0}}}.

3. The y-coordinate of the vertex is D. 

4. Find two other points, one on each side of the vertex.

5. Draw the graph.

----------------------

For your problem:

{{{y=-4abs(x+4)-3}}}

1.  The graph is an upside-down V since {{{-4}}} is negative.

2.  {{{x + 4 = 0}}}, so {{{x = -4}}} is the x-coordinate of
the vertex. (sharp point of the upside down V).

3,  The y-coordinate of the vertex is -3, so the vertex is (-4,-3).

4.  Substituting {{{x=-5}}} and {{{x=-3}}} in {{{y=-4abs(x+4)-3}}}
both give y=-7. So two other points are (-5,-7) and (-3,7).

5.

{{{graph(246,400,-6, 2, -10,3,-4abs(x+4)-3)}}}
    
Edwin</pre>