Question 246203
(a) Express the quadratic function in standard form.
(b) Find its vertex and its x and y intercepts.
Vertex occurs where x = -b/2a = -1/[2(2)] = -1/4
The corresponding y-value is f(-1/4) = 2(-1/4)^2+(-1/4)-6 = -6 1/8
Vertex: (-1/4 , -49/8)
---------------------------
(c) Sketch its graph. 
f(x) = 2X^2 + X - 6
-------------------
{{{graph(400,300,-10,10,-10,10,2x^2+2-6)}}}
===============================
Cheers,
Stan H.