Question 246173
Hello, 
Let's first get rid of the sq rt by squaring both sides. 
[sqrt(3x + 9)]^2 <= 3^2 This will give us:
3x+9<=9 Subtract 9 from both sides will be:
3x<=0 Divide both sides by 3 results in:
x<=0
Check this answer in the original problem. 
Does it work?
RJ Toftness
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