Question 246150
Given the setup:
{{{(y+5)(y-1) = 27}}}
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We can multiply through:
{{{y^2 -y +5y - 5 = 27}}}
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Collecting terms
{{{y^2 + 4y - 5 = 27}}}
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Subtracting 27 from both sides
{{{y^2 + 4y - 32 = 0}}}
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Can we factor 32 into two terms that are 4 apart?  4 * 8 = 32, so we have:
{{{(y+8)(y-4)=0}}}
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So we have to solutions: y = -8 and y = 4.
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Checking {{{y=-8}}}, we have:
{{{(y+5) = -8+5 = -3}}}
{{{(y-1) = -8-1 = -9}}}
{{{(y+5)(y-1) = (-3)(-9) = 27}}}
Check.
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Checking for {{{y = 4}}}, we have:
{{{(y+5) = 4+5 = 9}}}
{{{(y-1) = 4-1 = 3}}}
{{{(y+5)(y-1) = (3)(9) = 27}}}
Check.
Done.