Question 246150
(y+5)(y-1)=27
expand
y^2+4y-5=27
add 5 to both sides
y^2+4y=32
we will complete the square
take (4/2)^2 which =4
add 4 to both sides
y^2+4y+4=36
factor
(y+2)^2=36
get square root
y+2=+\-6
y+2=6
y+2=-6
subtract 2 from both sides
y=4
y=-8
see below for other ways to do it
*[invoke quadratic "x", 1, 4, -32 ]