Question 246109
Since there is no easy way to factor this equation, use the quadratic formula:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 

the general formula for a quadratic is 
{{{ax^2 + bx + c = 0}}}


Your equation is:
{{{3x^2 + x -5 = 0}}}


Therefore:
a=3
b=1
c=-5


Substitute and solve for x:

{{{x = (-(1)+- sqrt( 1^2-4*3*-5))/(2*3) }}}

 
{{{x = (-(1)+- sqrt( 1-(-60)))/6 }}} 


{{{x = (-(1)+- sqrt( 1+60))/6 }}}


{{{x = (-1 +- sqrt( 61))/6 }}}


There are 2 answers: (this are the x -coordinates of the points where the parabola crosses the x-axis):
{{{(-1 + sqrt(61))/6 = 1.135}}}
{{{(-1 - sqrt(61))/6 = 1.468}}}