Question 245960
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Since the angle from point A is 32 degrees and the angle from point B is 54 degrees, the angle between the two towers from the point of view of the fire would have to be 180 - (32 + 54) = 94 degrees.


Use the Law of Sines:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{a}{\sin(A)}\ =\ \frac{b}{\sin(B)}\ =\ \frac{c}{\sin(C)}]


So, you need to find the measure of side *[tex \Large a]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{a}{\sin(32)}\ =\ \frac{b}{\sin(54)}\ =\ \frac{22}{\sin(94)}]



*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a\ = \left(\frac{22}{\sin(94)}\right)\sin(32)]


Get out your calculator and make sure it is in Degree mode.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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