Question 245941
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No.  If the width is 12 meters, 2 meters longer than TWICE the width is 26 meters. This may be fine in a backyard with one dimension of 30 meters.  But then how is anyone here supposed to know what is appropriate?  Mathematically, a 10,000 meter by 20,002 meter rectangle fits the parameters of the problem and, for that matter, so does a 2.02 meter by 0.01 meter rectangle, but I'm certain such sizes violate some other criteria that you may have but have failed to share.  Give us a break.  We aren't clairvoyant.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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