Question 31268
A=P(1+nr)
=>P(1+nr)=A
=>(1+nr)=A/P (put restriction P not= 0)
=>1+nr=A/P
=>nr=(A/P)-1
=>r=(1/n)[(A/P)-1] (put restriction n not= 0)
=>r=(1/n)[(A-P)/P]

Answer: r=(A-P)/nP