Question 245825
The equation of a line in slope intercept form is:

y = m*x + b where m is the slope and b is the value of y where the line crosses the y-axis (this is actually the value of y when x is zero).

Since you know the slope m in this case is 2/3 you have: 

y = (2/3)*x + b

Since the point (3,-4) is a point on the line we know that:

-4 = (2/3)*3 + b

-4 = 2 + b
-2 = b

Substituting -2 for b in the equation above we get:

y = (2/3)*x -2 for the equation of the line