<PRE><B>Question 245777</B>
Given a level of confidence of 99% and a population standard deviation of 10, what other information is necessary:
(A) To find the Maximum Error of Estimate (E)?
Size of the sample.
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(B) To find the sample size (n)?
n = [z*s/E]^2
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(C) Given the above confidence level and population standard deviation, find the Maximum Error of Estimate (E) if n = 45. Show all your calculations. Show all work.
E = z*s/sqrt(n)
E =  2.576*10/sqrt(45) 
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(D) For this same sample of n = 45, what is the width of the confidence interval around the population mean? Show all work.
2E
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(E) Given this same confidence level and standard deviation, find n if E = 3.5. (Always round to the nearest whole person.) Show all work.
n = [z*s/E]^2
n = [2.576*10/3.5]^2
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Cheers,
Stan H.
</PRE>