Question 245805
I believe your problem is:
{{{ln(log(2,ln(x)))=0}}}
{{{log(2,ln(x)) = e^0}}}
{{{log(2,ln(x)) = 1 }}}
{{{ln(x) = 2^1 }}}
{{{ln(x) = 2 }}}
{{{x = e^2 }}}
{{{x = 7.389}}}