Question 245558
log 2 (x + 2) + log 2 (x - 4) = 4
2^(log 2 (x + 2)) * 2^( log 2 (x - 4)) =2^4
(x+2)(x-4)=16
x^2-2x-8=16
x^2-2x-24=0
(x-6)(x+4)=0
x=6
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Ed