Question 245409
You need to get the equation into the form:

(x-h)^2 = (y-k)^2 = r^2

This is the equation of a circle with center (h,k) and radius r.

Reorganizing the terms given we have:

(x^2 + 6x) + (y^2 + 2y) = - 6

"Complete the squares" for the x and y terms:

(x^2 + 6x + 9)+ (y^2 + 2y + 1) = -6 +9 + 1 = 4

Factoring the terms:

(x+3)^2 + (y+1)^2 = 4

Now the equation is in the form needed to find the center and the radius.