Question 245428
Since 6 is greater than 5 use f(x) = -4*x-3  
f(6) = -4*6 - 3 = ?

Since 0 is less than 5 use f(x) = 3x^2 - x + 1
f(0) = 3*(0^2) - 0 + 1 = ?

Since -3 is less than 5 use f(x) = 3x^2 - x + 1
f(-3) = 3*(-3)^2 - (-3) + 1 = ?