Question 245438
5x^2=-17x-6
we want to put it in the style of 
ax^2+bx+c=0
to move everything to one side we add 17x+6 to both sides
5x^2+17x+6=0
I suggest formula the quadratic formula
x=-b+-sqrt(b^2-4ac)/(2*a)
where a=5; b=17 and c=6
so we get b^2-4ac=17^2-4*5*6
Since 17^2-4*5*6 is greater than zero we will have two solutions.
continue plugging in the values a;b and c
the two solutions are
(-17+sqrt(17^2-4*5*6))/2*5
(-17-sqrt(17^2-4*5*6))/2*5