Question 164095
the product of two consecutive even integers is 168


Let the 1st integer be F


Then the 2nd consecutive even integer is F + 2


Since the product of the integers is 168, then we'll have: F(F + 2) = 168


{{{F^2 + 2F = 168}}}


{{{F^2 + 2F  - 168 = 0}}}


(F + 14)(F - 12) = 0


F = - 14 or 12


If the 1st even integer is - 14, then the second consecutive even integer is - 12. Or, if the 1st even integer is 12, then the second consecutive even integer is 14.


Therefore, the 2 integers are either {{{highlight_green(-14_and_-12)}}} or {{{highlight_green(12_and_14)}}}