Question 245212
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The area of a square is the measure of a side squared.  The perimeter of a square is 4 times the measure of a side, so:


Let *[tex \Large x] represent the measure of a side, then:



*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ =\ 4x\ +\ 165]


or, in standard form:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ -\ 4x\ -\ 165\ =\ 0]


Solve the factorable quadratic.  Discard the negative root.  The positive root is the measure of the side of the described square.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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