Question 31251
your factors are the correct ones.


{{{ (x^3+1)(x^3-3)=0 }}}


so {{{(x^3+1)=0}}} or {{{(x^3-3)=0}}}
{{{ x^3=-1 }}} or {{{ x^3 = 3 }}}
--> x=-1 or x=cuberoot of 3


jon.