Question 244552
Here is the answers with the solutions


(b.) n = 100 ____________ (3 points)
t(98) = (98-100)/[16/sqrt(100)] = -1.25
t(102) = (102-100)/[16/sqrt(100)] = +1.25
P(98 < x-bar < 102) = P(-1.25 < t < 1.25 when df = 49) = 

c.) n = 200 ____________ (3 points)
t(98) = (98-100)/[16/sqrt(200)] = -1.76
t(102) = (102-100)/[16/sqrt(200)] = +1.76
P(98 < x-bar < 102) = P(-1.76 < t < 1.76 when df = 49) = 

d.) n = 400 ____________ (3 points)
t(98) = (98-100)/[16/sqrt(400)] = -2.5
t(102) = (102-100)/[16/sqrt(400)] = +2.5
P(98 < x-bar < 102) = P(-2.5< t < 2.5 when df = 49) = 

How do I solve for P