Question 244851
{{{2^(logx)=4*x}}}


Take the log of each side:
{{{log(2^(logx))=log(4x)}}}

{{{logx*log2=log4+logx}}}

Subtract logx from each side:
{{{logx*log2-logx=log4}}}


Factor out the logx:
{{{(logx)(log2 -1)=log4}}}


Divide both sides by (log2-1):
{{{((logx)(log2-1))/(log2-1)=(log4)/(log2-1)}}}
{{{logx= (log4)/(log2-1)}}}


Finally, raise both sides as a power of 10:
{{{x=10^((log4)/(log2-1))}}}.


This comes out to approximately .137609.


I checked this with a graphing calculator, and it is correct!!!


Dr. Robert J. Rapalje, Retired
Seminole State College of Florida