Question 244814
Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(2,-4\right)]. So this means that {{{x[1]=2}}} and {{{y[1]=-4}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(7,3\right)].  So this means that {{{x[2]=7}}} and {{{y[2]=3}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(3--4)/(7-2)}}} Plug in {{{y[2]=3}}}, {{{y[1]=-4}}}, {{{x[2]=7}}}, and {{{x[1]=2}}}



{{{m=(7)/(7-2)}}} Subtract {{{-4}}} from {{{3}}} to get {{{7}}}



{{{m=(7)/(5)}}} Subtract {{{2}}} from {{{7}}} to get {{{5}}}



So the slope of the line that goes through the points *[Tex \LARGE \left(2,-4\right)] and *[Tex \LARGE \left(7,3\right)] is {{{m=7/5}}}