Question 31178
Given:
y/(y-2) + y/(y^2-4) = y + 3 /(y+2)

Solution:

y/(y-2) + y/[(y-2)(y+2)] = (y+3)/(y-2)

(y-2)(y+2){y/(y-2) + y/[(y-2)(y+2)] = (y+3)/(y-2)}

y(y+2) + y = (y+3)(y+2)

y^2 + 2y + y = y^2 + 5y + 6

y^2 - y^2 + 2y + y - 5y - 6 = 0 

-2y - 6 = 0

y + 3 = 0

y = -3

answere: y = -3