Question 31232
In a triangle, the second angle is twice the first and the third angle is 20 drgees less than the first. Find the measure of all three angles. 
LET FIRST ANGLE =A
SECOND ANGLE = 2*A
THIRD ANGLE = A-20
SUM OF ALL 3 ANGLES =A+2A+A-20=180
4A=180+20=200
A=200/4=50
SO THE 3 ANGLES ARE A=50,2*50=100,50-20=30.