Question 244639
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Let *[tex \Large x] represent the integer.


4 added to the square of the integer:  *[tex \Large x^2\ +\ 4]


5 less than 10 times the integer:  *[tex \Large 10x\ -\ 5]


The two quantities are equal because the questions says "the result is," so


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ +\ 4\ =\ 10x\ -\ 5]


Rearrange to standard form, then solve the quadratic.  Hint: It factors.  You will get two roots, only one of which is a composite integer. Discard the root that is not a composite integer and the remaining root is your answer.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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