Question 31221
Let the normal amount off student be x
<pre><b>If 10 students can't attend the expression will be: x-10
Equation:
*[tex \frac{960}{x}-\frac{960}{x-10}=16]
{{{960((x)-(x-10))=16((x)(x-10))}}}
{{{9600=16(x^2-10x)}}}
{{{16x^2-160x-9600=0}}}
{{{x^2-10x-600=0}}}
In quadratic formula, a=1, b=-10, c=-600
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
{{{x=(-(-10)+-sqrt((-10)^2-4*1*-600))/(2*1)}}}
{{{x=(10+-sqrt(100+2400))/2}}}
Remove the negative:
{{{x=(10+sqrt(2500))/2}}}
x=(10+50)/2
x=30
<font color = red>Hence, the total number of students attending was 30.
</font>Paul.