Question 244512
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Let *[tex \Large l] represent the length.  The width is then *[tex \Large \frac{l}{3}\ +\ 7].  The area is the length times the width, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ l\left(\frac{l}{3}+7\right)\ =\ 54]


A little manipulation results in:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ l^2\ +\ 21l\ -\ 162\ =\ 0]


Solve the quadratic for *[tex \Large l].  Hint: It factors.  Exclude the negative root because you are looking for a positive measure of length.  The positive root is the length, from which you should be able to easily calculate the width.  Multiply your results for length and width to make sure that you obtain a result of 54.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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