Question 31158
25-[2+5y-3(y+2)]=-3(2y-5)-[5(y-1)-3y+3] 
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             distribute the -3 and 5
25-2+5y-3y-6=-6y+15-5y-5-3y+3
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    combine all variables
17+2y=8-14y
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subtract seventeen from here ↑
2y=-9-14y
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add 14y to here↑
16y = -9