Question 31185
Let the smaller positive number be x
Let the larger positive number be x+5


(x)(x+5)=36
{{{x^2+5x-36=0}}}
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
a=1, b=5, c=-36
{{{x=(-5+-sqrt(5^2-4*1*-36))/(2*1)}}}
{{{x=(-5+-sqrt(25+144))/2}}} --> simplfy and reomve the negative:
{{{x=(-5+13)/2}}}
{{{x=8/2}}}
x=4
4+5=9
Hence, the two numbers are 4 and 9.
Paul.