Question 244092
Y=mX+b where m=slope & b=the y intercept.
a. A line that passes through (6,2) and has a slope of 2.
2=2*6+b
2=12+b
b=2-12
b=-10 The Y intercept.
Y=2X-10 ans.
b. A line that passes though the points (2,4) and (8,16)
slope=(Y2-Y1)/(X2-X1)=(16-4)/(8-2)=12/6=2
4=2*2+b
4=4+b
b=4-4
b=0 The Y intercept.
Y=2X ans.
c. A line that passes through (7,3) and has a slope of -1.
3=-1*7+b
3=-7+b
b=1+7
b=8 The Y intercept.
Y=-X+8 ans.
d. A line that passes through (1, 1) and is perpendicular to the line 3x+4Y=12.
3X+4Y=12
4Y=-3X+12
Y=-3X/4+12/4
Y=-3X/4+3 This line has a slope=-3/4. A perpendicular line will havwe a 
slope=4/3.
1=4/3*1+b
1=4/3+b
b=1-4/3
b=-1/3 The Yintercept. 
e. A circle with a radius of 9 and a midpoint at (3,3)
(X-3)^2+(Y-3)^2=9^2
I tried to graph this circle using the graphing formula, but could not draw the circle.