Question 31172
not sure exactly which is the triangle you are asking for. Label the vertices as A, B, C, D, E, F then draw a line between A and C...you mean the triangle ABC?


If so, we have Area=(1/2)absinC --> the notation here is nothing to do with the labelling of the vertices.


a=AB
b=BC


and a=b=4


angle C is angle ABC. This is an interior angle of a hexagon.




To find the interior angle of an hexagon:
A hexagon is 6sided. This can be divided into 4 triangles.
4 triangles have 4*180 angles between them --> 720degrees.


So each interior angle = 720/6 --> 120degrees


so area= (1/2)*4*4*sin120
8sin120
8*sqrt(3)/2
4sqrt(3) is the area of triangle ABC.


Hope this helps


jon.