Question 244003
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Let *[tex \Large x] represent the first integer.  Then *[tex \Large x\ +\ 1] is the next integer, and *[tex \Large x\ +\ 2] is the one after that.  Also, the square of 6 is 36.  So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ (x\ +\ 1)\ +\ (x\ + 2)\ = 36]


Solve for *[tex \Large x].  Then count.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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