Question 243385
find the measure of an angle such that the difference between the measures of its supplement and three times its complement is 10 degrees
:
Let = the angle
then
(180-x) = it's supplement
and
(90-x) = it's complement
:
The equation for:
"the difference between the measures of its supplement and three times its complement is 10 degrees"
(180-x) - 3(90-x) = 10
:
180 - x - 270 + 3x = 10
:
Combine like terms:
-x + 3x + 180 - 270 = 10
:
2x - 90 = 10
:
2x = 10 + 90
:
2x = 100
x = {{{100/2}}}
x = 50 degrees
:
:
Is this true?
(180-50) - 3(90-50) = 10
130 - 3(40) = 10; confirms our solution