Question 243639
The perimeter of a triangle = a + b + c.
where
a = first side
b = second side
c = third side
.
We are told P = 110.
.
To solve word problems, it usually is best to define these variables in terms of one another, which the problem tells you how to do so.  For example,
.
a = a
b = 2a
c = b+30 = 2a+30
.
110 = a + b + c
Substituting for 'b' and 'c' defined in terms of 'a'.
110 = a + 2a + 2a+30
Collecting terms
110 = 5a + 30
Subtract 30 from both sides
80 = 5a
Equals are equal, so
5a = 80
Divide both sides by 5
a = 16
.
Substituting back into the formulas we set up above.

b = 2a = 2(16) = 32
c = b + 30 = 32 + 30 = 62
.
Checking our work:
a + b + c = 16 + 32 + 62 = 110
Done.