Question 243593
{{{2/x + 3/y = (2y + 3x)/xy}}}
.
{{{3/x - 2/y = (3y - 2x)/xy}}}
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The division can be replaced by multiplication by the inverse.
So instead of:
{{{ ( (2y + 3x) / xy ) / ( (3y - 2x) / xy ) }}}
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we can substitute:
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{{{ ( (2y + 3x) / xy ) * ( xy / (3y - 2x) ) }}}
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The 'xy' terms will cancel, so we have:
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{{{ (2y + 3x) / (3y - 2x) }}}