Question 243583

Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(5,8\right)]. So this means that {{{x[1]=5}}} and {{{y[1]=8}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(10,-10\right)].  So this means that {{{x[2]=10}}} and {{{y[2]=-10}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(-10-8)/(10-5)}}} Plug in {{{y[2]=-10}}}, {{{y[1]=8}}}, {{{x[2]=10}}}, and {{{x[1]=5}}}



{{{m=(-18)/(10-5)}}} Subtract {{{8}}} from {{{-10}}} to get {{{-18}}}



{{{m=(-18)/(5)}}} Subtract {{{5}}} from {{{10}}} to get {{{5}}}



So the slope of the line that goes through the points *[Tex \LARGE \left(5,8\right)] and *[Tex \LARGE \left(10,-10\right)] is {{{m=-18/5}}}