Question 243530
{{{7x^2+28x=49}}} Start with the given equation.



{{{7(x^2+4x)=49}}} Factor out the GCF 7 from the left side.



{{{x^2+4x=49/7}}} Divide both sides by 7.



{{{x^2+4x=7}}} Reduce



{{{x^2+4x+highlight(4)=7+highlight(4)}}} Take half of the 'x' coefficient and square it to get 4. Add this number to both sides.



{{{(x+2)^2=11}}} Factor the left side and combine like terms on the right.



{{{x+2=""+-sqrt(11)}}} Take the square root of both sides.



{{{x=-2+-sqrt(11)}}} Subtract 2 from both sides to isolate 'x'.



So the solutions are {{{x=-2+sqrt(11)}}} or {{{x=-2-sqrt(11)}}}