Question 243527


{{{x+8y=16}}} Start with the given equation.



{{{8y=16-x}}} Subtract {{{x}}} from both sides.



{{{8y=-x+16}}} Rearrange the terms.



{{{y=(-x+16)/(8)}}} Divide both sides by {{{8}}} to isolate y.



{{{y=((-1)/(8))x+(16)/(8)}}} Break up the fraction.



{{{y=-(1/8)x+2}}} Reduce.



So the equation {{{y=-(1/8)x+2}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=-1/8}}} and the y-intercept is {{{b=2}}} note: the y-intercept is the point *[Tex \LARGE \left(0,2\right)]