Question 243420
Assuming this is your equation {{{5^(x-6)-5^(-x)=0}}}?

{{{5^(x-6)=5^(-x)}}}
{{{log(base 5) 5^(x-6)= log(base 5) 5^(-x)}}}
{{{x-6= -x}}}
{{{2x= 6}}}
{{{x= 3}}}