Question 31118
{{{ (3x^3(-2x)^4)/(24x^5) }}}


--> {{{ (-2x)^4 }}} is (-2x)(-2x)(-2x)(-2x) --> {{{(4x^2)(4x^2)}}} --> {{{16x^4}}}


So, {{{ (3x^3(-2x)^4)/(24x^5) }}} becomes {{{ (3x^3(16x^4))/(24x^5) }}}
{{{ (48x^7)/(24x^5) }}}
{{{ (2x^7)/(x^5) }}}
{{{ 2x^2 }}}


jon.