Question 243372
CORRECTION.
It turns out the term '8p*8' is really '8p - 8'...so that is entirely different problem than the one originally solved.
.

Simplify:
{{{
((2p-2)/p)*((6p^2)/(8p-8))
}}}
.
Since you are multiplying, you can simply multiply numerator times numerator and denominator times denominator.
{{{
((2p-2)(6p^2))/(p*(8p-8))
}}}
.
{{{
(12p^3-12p^2)/(8p^2-8p)
}}}
.
{{{
(12p(p^2-p))/(8p(p-1))
}}}
.
{{{
(3*4*p(p^2-p))/(2*4*p(p-1))
}}}
.
Note the 4p will cancel in the numerator and denominator.
So we arrive at:
{{{
(3(p^2-p))/(2(p-1))
}}}
We can factor the numerator by extracting the common 'p'
{{{
(3p(p-1))/(2(p-1))
}}}
Now the (p-1) terms will cancel, leaving us with
{{{
3p/2 = (3/2)p
}}}